Posts Tagged ‘intersection’
4
Mar
Posted by mathispower4u in 6. Calculus Videos . Tagged: accumulation , application , cars , definite , function , integration , intersection , passing , rate , through , total . Leave a Comment
This video provides an example of an application problem using a definite integral to determine the number of cars passing through an intersection during a specific interval of time.
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14
Jan
Posted by mathispower4u in 6. Calculus Videos . Tagged: application , arc , calculus , definite , equations , integral , integrate , integration , intersection , interval , length , loop , parameter , parametric . Leave a Comment
This video provides an example of how to determine the arc length of a loop of a plane curve given by parametric equations.
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10
Sep
Posted by mathispower4u in 3. Algebra Videos . Tagged: coordinate , equation , graph , graphically , intersection , linear , one , point , solution , solve , variable . Leave a Comment
This video explains how to solve a linear equation in one variable by graphing using the TI84. The intersection method is used.
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10
Sep
Posted by mathispower4u in 3. Algebra Videos , 7. Linear Algebra . Tagged: coordinate , graph , graphically , inequalities , inequality , intersection , linear , one , point , solution , solve , variable . Leave a Comment
This video explains how to solve a linear inequality in one variable by graphing using the TI84. The intersection method is used.
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3
Sep
Posted by mathispower4u in 3. Algebra Videos , 7. Linear Algebra . Tagged: algbra , augmented , consistent , echelon , elimination , equations , form , gaussian , graph , independent , intersection , linear , matrices , matrix , operations , reduced , row , solution , solve , system , three , two , verify . Leave a Comment
This video explains how to solve a system of equations by writing an augmented matrix in reduced row echelon form. This example has one solution.
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3
Sep
Posted by mathispower4u in 3. Algebra Videos , 7. Linear Algebra . Tagged: algbra , augmented , consistent , echelon , elimination , equations , form , gaussian , graph , independent , intersection , linear , matrices , matrix , operations , reduced , row , solution , solve , system , two , verify . Leave a Comment
This video explains how to solve a system of equations by writing an augmented matrix in reduced row echelon form. This example has one solution.
VIDEO
3
Sep
Posted by mathispower4u in 3. Algebra Videos , 7. Linear Algebra . Tagged: algebra , augmented , echelon , elimination , equations , form , gaussian , graph , inconsistent , intersection , linear , matrices , matrix , no , operations , reduced , row , solution , solve , system , two , verify . Leave a Comment
This video explains how to solve a system of equations by writing an augmented matrix in reduced row echelon form. This example has no solution.
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3
Sep
Posted by mathispower4u in 3. Algebra Videos , 7. Linear Algebra . Tagged: algebra , augmented , consistent , dependent , echelon , elimination , equations , form , gaussian , graph , intersection , linear , matrices , matrix , operations , reduced , row , solution , solve , system , two , verify . Leave a Comment
This video explains how to solve a system of equations by writing an augmented matrix in reduced row echelon form. This example has an infinite number of solutions.
VIDEO
19
Jul
Posted by mathispower4u in 6. Calculus Videos . Tagged: c , constant , continuity , continuous , determine , everywhere , find , inequality , intersection , interval , solve . Leave a Comment
This video explains how to determine what the intervals must be for each piece of a piece-wise defined function must be in order for the function to be continuous everywhere.
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19
Jul
Posted by mathispower4u in 6. Calculus Videos . Tagged: c , constant , continuity , continuous , determine , everywhere , find , inequality , intersection , interval , solve . Leave a Comment
This video explains how to determine the value of a constant in a one of the function rules of a piece-wise defined function in order for the function to be continuous everywhere.
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